(x+1)(3x^2-12)=0

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Solution for (x+1)(3x^2-12)=0 equation: 


Simplifying
(x + 1)(3x2 + -12) = 0

Reorder the terms:
(1 + x)(3x2 + -12) = 0

Reorder the terms:
(1 + x)(-12 + 3x2) = 0

Multiply (1 + x) * (-12 + 3x2)
(1(-12 + 3x2) + x(-12 + 3x2)) = 0
((-12 * 1 + 3x2 * 1) + x(-12 + 3x2)) = 0
((-12 + 3x2) + x(-12 + 3x2)) = 0
(-12 + 3x2 + (-12 * x + 3x2 * x)) = 0
(-12 + 3x2 + (-12x + 3x3)) = 0

Reorder the terms:
(-12 + -12x + 3x2 + 3x3) = 0
(-12 + -12x + 3x2 + 3x3) = 0

Solving
-12 + -12x + 3x2 + 3x3 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '3'.
3(-4 + -4x + x2 + x3) = 0

Ignore the factor 3.

Subproblem 1
Set the factor '(-4 + -4x + x2 + x3)' equal to zero and attempt to solve:

Simplifying
-4 + -4x + x2 + x3 = 0

Solving
-4 + -4x + x2 + x3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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